Chapter+2

**__Chapter 2__**  __Mass of each KG of element-In 100kg of the hot metal (%)__ Iron (Fe) - 94.9 Carbon (C) - 4.55 Silicon (Si) - 0.25 Manganese (Mn) - 0.3

__How many KG of each element are oxidised?__ FE efficiency 98%.

Iron - 0.98% of 94.9 = 0.98 x 94.9 = 93kg Carbon - 4.5% of 4.55 = 0.045 x 4.55 = 0.2kg Manganese - 0.1% of 0.3 = 0.1 x 0.3 = 0.03 (0.27kg are oxidised) All Si (Silicon) is oxidised __Amount of Energy generated from oxidation __ From Iron (Fe) 4.3 x 1.898 = 8.1614 From Carbon (C) 11.7 x 4.5 = 52.65 From Silicon (Si) 33.9 x 0.25 = 8.5 From Manganese (Mn) 7.4 x 0.2 = 1.48 8.1614+ 52.65 + 8.5 + 1.48 = 70.6 Mj  __How much energy is used from natural gas in a hosue in a year?__

2000 x 32Mj = 64000Mj __How much energy is given out from oxidation of the steel mix?__

100kg of steel mixture gives us 70.6 Mj of energy. To find the amount that would give us 64000Mj 64000 / 70.6 = 906Kg __What will be the remaining temperature of the hot metal mixture? __  When 1kg of carbon is oxidised it generates 11.7mj of energy. Out of the 4.55kg of carbon is the mixture 0.05kg becomes part of the steel. This mean that 4.5kg of carbon is oxidised.

4.5 x 11.7mj = 56.65mj 45 % of this leaves as waste energy so we are left with 55% of the energy in the reaction. 55% is 0.55 as a decimal so 0.55% x 56.65mj (the energy) = 28.96Mj left

When all of the oxidisations have taken place Only 0.05% of the carbon used goes into the steel. So how much is oxidised%